Fruta XYZ
Solución: Si hay x manzanas, hay 256-x peras.
(x-12)/3=(256-x-8)/4
x/3-12/3=256/4-x/4-8/4
x/3-4=64-x/4-2
x/3=64-2 4-x/4
x/3= 66-x/4
66=x/3 x/4
66=7/12x
x=66*12/7
x=()
(x-12)/3=(256-x-8)/4
x/3-12/3=256/4-x/4-8/4
x/3-4=64-x/4-2
x/3=64-2 4-x/4
x/3= 66-x/4
66=x/3 x/4
66=7/12x
x=66*12/7
x=()